From @mail.uunet.ca:mark.longridge@canrem.com Sat Jan 7 00:27:55 1995 Return-Path: <@mail.uunet.ca:mark.longridge@canrem.com> Received: from seraph.uunet.ca (uunet.ca) by life.ai.mit.edu (4.1/AI-4.10) for /com/archive/cube-lovers id AA04016; Sat, 7 Jan 95 00:27:55 EST Received: from portnoy.canrem.com ([198.133.42.17]) by mail.uunet.ca with SMTP id <124322-2>; Sat, 7 Jan 1995 00:14:48 -0500 Received: from canrem.com by portnoy.canrem.com (4.1/SMI-4.1) id AA10950; Sat, 7 Jan 95 00:10:52 EST Received: by canrem.com (PCB-UUCP 1.1f) id 1C7919; Fri, 6 Jan 95 23:57:55 -0500 To: cube-lovers@life.ai.mit.edu Reply-To: CRSO.Cube@canrem.com Sender: CRSO.Cube@canrem.com Subject: Cube terms From: mark.longridge@canrem.com (Mark Longridge) Message-Id: <60.938.5834.0C1C7919@canrem.com> Date: Fri, 6 Jan 1995 23:50:00 -0500 Organization: CRS Online (Toronto, Ontario) Martin Schoenert states: > Only one out of 332640 elements of GE (and of G) centralizes P. > That is to say that the index of the centralizer of P in GE has index > 332640 in GE. Since all elements of GC commute with all elements of > GE, the index of the centralizer of P in G also has index 332640 in G. > Z is indeed the center of GE', GE, G, G', and GCE. I get the fact that only the super-flip (or 12-flip) is the centre of G and the centre of GE. Another way to look at it would be the centre of the cube group must effect all the corners & edges in the same way, and only the super-flip fits these conditions when we allow all 6 generators < U, D, F, B, L, R > to be used. In the case of the smaller group < U, R > we can get 6 corners twisted either clockwise or counter-clockwise, thus effecting all the corners and edges the same, due to the fact we can have 6 twists the same and < U, R > only contains 6 corners, and so this is the centre of < U, R >. But I don't understand how only one out of 332,640 elements of GE and G centralizes P. I thought that GE had: (12 ^ 2 / 2 ) * 12! = 980,995,276,800 elements That is to say that the group on the cube of edges only has 980,995,276,800 elements. To be honest I'm not sure what P represents! Jerry refers to P as the Pons Asinorum, but I think the term may have two meanings in the two messages. Z is the centre of G right? I need an ANSI standard math dictionary, but I doubt such a book exists. I'm going to tackle some more cube terminology in my next message. -> Mark <- Email: mark.longridge@canrem.com