From hoey@aic.nrl.navy.mil Sun Dec 17 02:47:48 1995 Received: from Sun0.AIC.NRL.Navy.Mil by life.ai.mit.edu (4.1/AI-4.10) for /com/archive/cube-lovers id AA02363; Sun, 17 Dec 95 02:47:48 EST Received: from sun13.aic.nrl.navy.mil by Sun0.AIC.NRL.Navy.Mil (4.1/SMI-4.0) id AA24215; Sun, 17 Dec 95 02:47:47 EST Return-Path: Received: by sun13.aic.nrl.navy.mil; Sun, 17 Dec 95 02:47:46 EST Date: Sun, 17 Dec 95 02:47:46 EST From: hoey@aic.nrl.navy.mil Message-Id: <9512170747.AA27428@sun13.aic.nrl.navy.mil> To: Cube-Lovers@life.ai.mit.edu Subject: Re: Presenting Rubik's Cube For the benefit of Cube-Lovers, here is rusin@washington.math.niu.edu (Dave Rusin)'s remark on finding a presentation of Rubik's cube. You have a group Rubik generated by the 6 90-degree rotations g_i. Let F be the free group on 6 generators x_i and f: F --> Rubik the obvious homomorphism. There is a big kernel N of f. (It is actually a free group: subgroups of free groups are free). You wish to find the smallest (free) subgroup K of N such that N is the normal closure of K in F. (When you give a presentation of Rubik in the form Rubik = , you are implicitly describing K as the subgroup of F generated by the corresponding words in the x_i.) To give this process at least a chance of success, you abelianize it: Let N_ab be the free abelian group N/[N,N], so that there is a natural map from N into N_ab. Since N is normal in F and [N,N] is characteristic in N, the action of F by conjugation on N lifts to an action of F on N_ab; even better, the subgroup N < F acts trivially on N_ab, so that F/N (i.e., the Rubik group itself) acts on N_ab. We think of N_ab as a Rubik-module (or better, as a Z[Rubik]-module). The subgroup K < N also maps to a subgroup K[N,N]/[N,N] of N_ab; significantly, N is the F-closure of K iff N=[K,F]K so that N_ab is generated as a Z[Rubik]-module by F. Thus, the question of what constitutes a minimal set of relations is the same as asking for the number of generators needed for a certain Rubik-module. (Of course, while you're at it, you might as well ask for a whole presentation or resolution of the Rubik-module. Inevitably, you will be led to questions of group cohomology.) He also included GAP's help file on the cube, which I think has been posted here already. Dan Hoey@AIC.NRL.Navy.Mil