From cube-lovers-errors@curry.epilogue.com Wed Jun 5 22:17:39 1996 Return-Path: cube-lovers-errors@curry.epilogue.com Received: from curry.epilogue.com (localhost [127.0.0.1]) by curry.epilogue.com (8.6.12/8.6.12) with SMTP id WAA08111 for ; Wed, 5 Jun 1996 22:17:38 -0400 Precedence: bulk Errors-To: cube-lovers-errors@curry.epilogue.com Date: Wed, 5 Jun 1996 16:47:13 -0400 Message-Id: <199606052047.QAA21223@chara.BBN.COM> From: Allan Wechsler To: cmaggs@glam.ac.uk Cc: CUBE-LOVERS@ai.mit.edu In-Reply-To: <96060509302127@glam.ac.uk> (message from VANESSA PARADIS WANTS ME on Wed, 5 Jun 1996 09:30:21 +0100) Reply-To: awechsle@bbn.com Date: Wed, 5 Jun 1996 09:30:21 +0100 From: VANESSA PARADIS WANTS ME To have a bit more challange when doing the cube, complete it so that each horizontal slice, is 1 turn (quarter of a full circle) out of place. Therefore, top and bottom face are one colour, but all side faces contain 3 colours. I'm not sure I understand this modified goal. Isn't this achieved by solving the cube aas usual, and then giving the top and bottom faces a clockwise quarter twist? Then the top and bottom are solid, and the sides are tricolor horizantal stripes. Even if I haven't understood the goal position, solving for any achievable position is not in principle harder than solving for any other. There might be perceptual problems, but surely these would go away after a little practice, no matter what the goal configuration. -A