From cube-lovers-errors@mc.lcs.mit.edu Mon Dec 14 15:00:05 1998 Return-Path: Received: from sun28.aic.nrl.navy.mil (sun28.aic.nrl.navy.mil [132.250.84.38]) by mc.lcs.mit.edu (8.9.1a/8.9.1-mod) with SMTP id PAA11876 for ; Mon, 14 Dec 1998 15:00:04 -0500 (EST) Precedence: bulk Errors-To: cube-lovers-errors@mc.lcs.mit.edu Date: Thu, 10 Dec 1998 23:04:10 -0500 From: michael reid Message-Id: <199812110404.XAA03343@cauchy.math.brown.edu> To: cube-lovers@ai.mit.edu Subject: fixing edge parity on 4x4x4 several people have posted maneuvers for "fixing" the edge parity on rubik's revenge. i haven't seen any maneuvers as short as mine (although there might be some disagreement about "length"). recall that i am using the notation _R_ (R underscored) to mean turn the outer two layers together. to switch the two UF edges: _R2_ B2 L U2 l U2 r' U2 r U2 F2 r F2 _L'_ B2 _R2_ side effects: rotates the set of 4 U centers by 180 degrees. also makes a 4-cycle of internal (0 faces visible) cubies. if you're not concerned about moving centers, use _(R2 B)_ u _(B' D2 B)_ u' _B_ l _(B2 D2 R2)_ here, _( ... )_ means the whole thing inside the parentheses is underlined. the maneuver that i normally use, since it's appropriate for my solving method, is U2 (r U2)^5 which makes a 4-cycle of edges in the r-slice (and also rotates the set of 4 U centers by 180 degrees). this one is short and easy to remember! these maneuvers all work well on the 5x5x5 also. mike